document.write( "Question 543415:  On a standardized test of mathematical ability, Kim scored a 40, and John scored a 20.60. The distribution of test scores for the population is normal, with a mean of 33 and a standard deviation of 6.3
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document.write( "The percentatge of the population which scored below John is  z= x- x bar/standard deviation.\r
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document.write( "The percentage of the population which scored above Kim is ?\r
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document.write( "The percentage of t he population between joh and kim is ? \n" );
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| Algebra.Com's Answer #354829 by stanbon(75887)      You can put this solution on YOUR website! On a standardized test of mathematical ability, Kim scored a 40, and John scored a 20.60. \n" ); document.write( "The distribution of test scores for the population is normal, \n" ); document.write( "with a mean of 33 and a standard deviation of 6.3 \n" ); document.write( "------------ \n" ); document.write( "Kim: z(40) = (40-33)/6.3 = 1.11 \n" ); document.write( "--------------------------- \n" ); document.write( "John: z(20.6) = (20.6-33)/6.3 = -1.9683 \n" ); document.write( "-------- \n" ); document.write( "The percentage of the population which scored below John ? \n" ); document.write( "? = P(z < -1.9683) = 0.0245 \n" ); document.write( "-------------------------------- \n" ); document.write( "The percentage of the population which scored above Kim is ? \n" ); document.write( "? = P(z > 1.11) = 0.1335 \n" ); document.write( "-------------------------------- \n" ); document.write( "The percentage of the population between joh and kim is ? \n" ); document.write( "? = 1-(0.0245+0.1335) = 0.8420 \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " \n" ); document.write( " |