document.write( "Question 538167: I need help working this problem out. I have no idea what I am doing.
\n" ); document.write( "4a + 2b - 6c = 2
\n" ); document.write( "6a + 3b - 9c = 3
\n" ); document.write( "8a + 4b - 12c = 6
\n" ); document.write( "

Algebra.Com's Answer #354780 by jpg7n16(66)\"\" \"About 
You can put this solution on YOUR website!
The idea behind a more complicated problem like this is to make things as easy as possible. For instance, start reducing everything. Equation 1 is all multiples of 2. #2 is multiples of 3. And #3 is multiples of 4 (except the 6) - but it's worth reducing anyways.
\n" ); document.write( ".
\n" ); document.write( "The ultimate goal is to eliminate one/two of the variables to solve for the rest.
\n" ); document.write( ".
\n" ); document.write( "Step 1: reduce all the coefficients down by dividing by 2, 3 and 4 respectively
\n" ); document.write( "1) \"2a%2Bb-3c=1\"
\n" ); document.write( "2) \"2a%2Bb-3c=1\"
\n" ); document.write( "3) \"2a%2Bb-3c=3%2F2\"
\n" ); document.write( ".
\n" ); document.write( "And something's wrong with this problem. 2 equations are NEVER supposed to be identical after reducing. And you'll notice #1 and #2 are equal. (So one of them is irrelevant)
\n" ); document.write( ".
\n" ); document.write( "But worse than that, we know that if a=b and a=c then b=c, right? Well according to your problem:
\n" ); document.write( "Since \"2a%2Bb-3c=1\" and \"2a%2Bb-3c=3%2F2\", then \"1=3%2F2\" - which is def not true.
\n" ); document.write( ".
\n" ); document.write( "So there you have it. There's something wrong with the problem! It's not your fault :-)
\n" ); document.write( "
\n" );