document.write( "Question 539439: How Do You Solve This Problem In Substitution Method?
\n" ); document.write( "x + y = 4
\n" ); document.write( "Y=2x+1
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Algebra.Com's Answer #354772 by jpg7n16(66)\"\" \"About 
You can put this solution on YOUR website!
My understanding is that for substitution method, you just plug in the \"Y=\" formula were Y used to be and solve.
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\n" ); document.write( "If \"Y=2x%2B1\"
\n" ); document.write( "then
\n" ); document.write( "\"x%2By=4\"
\n" ); document.write( "\"x%2B%282x%2B1%29=4\"
\n" ); document.write( "\"x%2B2x%2B1=4\"
\n" ); document.write( "\"3x=3\"
\n" ); document.write( "\"x=1\"
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\n" ); document.write( "Then plug that answer back into the Y= formuala
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\n" ); document.write( "\"Y=2x%2B1\"
\n" ); document.write( "\"Y=2%281%29%2B1\"
\n" ); document.write( "\"Y=2%2B1=3\"
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\n" ); document.write( "So your answer is, x=1 and y=3. (1,3)
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