document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=543006>Question 543006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I've been trying to figure out the answer on the 3 variables equations but i can't find the solution. Supposibly the solution are whole numbers. Can you help me get the answer :\r<BR>\n" );
document.write( "\n" );
document.write( "3a - 2b + 7c = 13<BR>\n" );
document.write( "a + 8b - 6c = -47<BR>\n" );
document.write( "7a - 9b -9c = -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354731 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying 2nd eqn by -3 and adding to 1st eqn (eliminating \"a\") ___ -26b + 25c = 154  (A)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiplying 2nd eqn by -7 and adding to 3rd eqn (eliminating \"a\") ___ -65b + 33c = 326  (B)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiplying eqn (A) by -5 and adding to 2 times eqn (B) (eliminating \"b\") ___ -59c = -118\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "solve for c, and substitute back to find a and b </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );