document.write( "Question 542706: a kayaker goes 12 mph in still water. if the river's current is 5 mph how long will it take to go 20 miles upstream? \n" ); document.write( "

Algebra.Com's Answer #354658 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+c+\"$ = speed of current
\n" ); document.write( "Let $\"+k+\"$ = kayaker's speed in still water
\n" ); document.write( "Let $\"+t+\"$ = time to go 20 miles upstream
\n" ); document.write( " $\"+k+-+c+\"$ = speed going upstream
\n" ); document.write( "given:
\n" ); document.write( " $\"+c+=+5+\"$ mi/hr
\n" ); document.write( " $\"+k+=+12+\"$ mi/hr
\n" ); document.write( "-----------
\n" ); document.write( " $\"+20+=+%28k+-+c%29%2At+\"$
\n" ); document.write( " $\"+20+=+%2812+-+5%29%2At+\"$
\n" ); document.write( " $\"+t+=+20+%2F+7+\"$
\n" ); document.write( " $\"+t+=+2.857+\"$ hrs
\n" ); document.write( " $\"+.857%2A60+=+51+\"$ min
\n" ); document.write( "It will take the kayaker 2 hrs and 51 min
\n" ); document.write( " \n" ); document.write( "

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