document.write( "Question 542538: the length of a rectangle is 7 feet less than twice its width and its perimeter is 160 feet
\n" ); document.write( "what is the area in square footage
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #354633 by lmeeks54(111)\"\" \"About 
You can put this solution on YOUR website!
Let L = the length of the long sides
\n" ); document.write( "Let W = the length of the short sides
\n" ); document.write( "Let A = the area of the rectangle
\n" ); document.write( "Let P = the perimeter of the rectangle
\n" ); document.write( "...
\n" ); document.write( "A = L * W
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "...
\n" ); document.write( "Given:
\n" ); document.write( "L = 2W - 7
\n" ); document.write( "P = 160
\n" ); document.write( "...
\n" ); document.write( "Substitution allows us to consider our system of 2 equations with two unknowns into 1 equation with one unknown. We already have L given in terms of W, so substitute that into the equation for P:
\n" ); document.write( "...
\n" ); document.write( "P = 160
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "160 = 2(2W - 7) + 2W
\n" ); document.write( "...
\n" ); document.write( "Combine like terms and simplify:
\n" ); document.write( "160 = 4W - 14 + 2W
\n" ); document.write( "160 + 14 = 4W + 2W
\n" ); document.write( "174 = 6W
\n" ); document.write( "174/6 = W
\n" ); document.write( "W = 29
\n" ); document.write( "...
\n" ); document.write( "go back to the equation for L:
\n" ); document.write( "L = 2W - 7
\n" ); document.write( "L = 2(29) - 7
\n" ); document.write( "L = 51
\n" ); document.write( "...
\n" ); document.write( "the dimensions of the rectangle are:
\n" ); document.write( "L = 51 ft
\n" ); document.write( "W = 29 ft
\n" ); document.write( "...
\n" ); document.write( "The problem asks for the area of the rectangle:
\n" ); document.write( "A = 51 ft * 29 ft
\n" ); document.write( "...
\n" ); document.write( "A = 1,479 ft^2
\n" ); document.write( "...
\n" ); document.write( "Check your work:
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "P = 160
\n" ); document.write( "P = 2(51) + 2(29)
\n" ); document.write( "P = 102 + 58
\n" ); document.write( "P = 160 checks
\n" ); document.write( "...
\n" ); document.write( "Cheers,
\n" ); document.write( "Lee
\n" ); document.write( "
\n" );