document.write( "Question 542528: I have to find the vertex, axis of symmetry, minimum or maximum value, and range of the parabola. the formula is y=ax^2+bx+c
\n" ); document.write( "Question: y=2x^2-6x+3
\n" ); document.write( "What i have so far:
\n" ); document.write( "y=2x^2-6x+3
\n" ); document.write( "-b/2a=-(-6)/2(2)=6/4=3/2
\n" ); document.write( "y=2(3/2)^2-6(3/2)+3
\n" ); document.write( " 2(9/4)-(-18)/2
\n" ); document.write( "I am stuck, I'm not sure if im doing it right but if you could help explain it to me that would be awsome! thank you!
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Algebra.Com's Answer #354630 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
\"y+=+2x%5E2-6x%2B3\"
\n" ); document.write( "You have correctly found the x-coordinate of the vertex:
\n" ); document.write( "\"x+=+3%2F2\" and you have made a start on finding the corresponding y-coordinate by substituting \"x+=+3%2F2\" into the given quadratic equation to solve for y.
\n" ); document.write( "\"y+=+2%283%2F2%29%5E2-6%283%2F2%29%2B3\" Simplify.
\n" ); document.write( "\"y+=+2%289%2F4%29-6%283%2F2%29%2B3\"
\n" ); document.write( "\"y+=+9%2F2-18%2F2%2B6%2F2\"
\n" ); document.write( "\"y+=+-3%2F2\"
\n" ); document.write( "The coordinates of the vertex are: (3/2, -3/2)
\n" ); document.write( "The vertex is a minimum (the parabola opens upward) which is indicated by the positive coefficient of the \"x%5E2\" term.
\n" ); document.write( "The axis of symmetry is give by \"x+=+3%2F2\" which is the equation of the vertical line passing through the point (3/2, -3/2). (the vertex.)
\n" ); document.write( "The range consists of all of the valid y-values.
\n" ); document.write( "Since the y=coordinate of the vertex (a minimum) is \"y+=+-3%2F2\" it is clear that the range is \"-3%2F2\" and above.
\n" ); document.write( "So the range can be written as:
\n" ); document.write( "\"y%3E=-3%2F2\"
\n" ); document.write( "You can see this from the graph:
\n" ); document.write( "\"graph%28400%2C400%2C-5%2C5%2C-3%2C10%2C2x%5E2-6x%2B3%29\"
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