document.write( "Question 542528: I have to find the vertex, axis of symmetry, minimum or maximum value, and range of the parabola. the formula is y=ax^2+bx+c
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document.write( "Question: y=2x^2-6x+3
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document.write( "What i have so far:
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document.write( "y=2x^2-6x+3
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document.write( "-b/2a=-(-6)/2(2)=6/4=3/2
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document.write( "y=2(3/2)^2-6(3/2)+3
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document.write( " 2(9/4)-(-18)/2
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document.write( "I am stuck, I'm not sure if im doing it right but if you could help explain it to me that would be awsome! thank you! \n" );
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Algebra.Com's Answer #354630 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You have correctly found the x-coordinate of the vertex: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The coordinates of the vertex are: (3/2, -3/2) \n" ); document.write( "The vertex is a minimum (the parabola opens upward) which is indicated by the positive coefficient of the \n" ); document.write( "The axis of symmetry is give by \n" ); document.write( "The range consists of all of the valid y-values. \n" ); document.write( "Since the y=coordinate of the vertex (a minimum) is \n" ); document.write( "So the range can be written as: \n" ); document.write( " \n" ); document.write( "You can see this from the graph: \n" ); document.write( " |