document.write( "Question 53187: A nut mixture contains 10% cashews. How many kilograms of the mixture and how many kilograms of cashews should be mixed to give 6 Kg of a nut mixture which is 25% cashews? \n" ); document.write( "
Algebra.Com's Answer #35463 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A nut mixture contains 10% cashews. How many kilograms of the mixture and how many kilograms of cashews should be mixed to give 6 Kg of a nut mixture which is 25% cashews? \n" ); document.write( ": \n" ); document.write( "Let x = the amt of 100% cashews; then (6-x) = amt of 10% mixture \n" ); document.write( ": \n" ); document.write( "Write a per cent cashews equation: \n" ); document.write( "1.0x + .10(6-x) = .25(6) \n" ); document.write( ": \n" ); document.write( "1x + .6 - .1x = 1.5 \n" ); document.write( ": \n" ); document.write( "1x - .x = 1.5 - .6 \n" ); document.write( ": \n" ); document.write( " .9x = .9 \n" ); document.write( ": \n" ); document.write( " x = .9/.9 \n" ); document.write( ": \n" ); document.write( " x = 1 kg of the 100% cashews required \n" ); document.write( ": \n" ); document.write( "6 - 1 = 5 kg of the 10% mixture \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( " 1(1) + .1(5) = .25(6) \n" ); document.write( " 1 + .5 = 1.5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |