document.write( "Question 542532: The problem says \"A cylindrical tank has a volume of 300 gallons. A similar tank next to it has dimensions that are 3 times as large. What is the volume of the larger tank?\"
\n" ); document.write( "I was thinking that you would multiply the volume of the first tank by 3. But then again i'm not that sure! Please help!
\n" ); document.write( "

Algebra.Com's Answer #354618 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i would think this means that the larger tank is 3 times as high and 3 times as wide.
\n" ); document.write( "if we assume that the smaller tank has a height of h and a diameter of 2r, then the larger tank would have a height of 3h and a diameter of 6r.
\n" ); document.write( "the volume of the smaller tank is equal to:
\n" ); document.write( "pi * r^2 * h
\n" ); document.write( "h is the height
\n" ); document.write( "r is the radius
\n" ); document.write( "the radius is equal to 1/2 the length of the diameter.
\n" ); document.write( "the volume of the larger tank would therefore be equal to:
\n" ); document.write( "pi * (3 * r)^2 * (3 * h)
\n" ); document.write( "this becomes:
\n" ); document.write( "pi * 3^2 * r^2 * 3 * h which becomes:
\n" ); document.write( "pi * 9 * r^2 * 3 * h which becomes:
\n" ); document.write( "pi * 27 * r^2 * h
\n" ); document.write( "based on this, the volume of the larger tank should be 27 times larger than the volume of the smaller tank.
\n" ); document.write( "volume of the smaller tank is pi * r^2 * h
\n" ); document.write( "volume of the larger tank is pi * 27 * 4^2 * h
\n" ); document.write( "divide the volume of the larger tank by the volume of the smaller tank and you get a ratio of 27 / 1 which is equal to 27.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );