document.write( "Question 542438: Andrew invests a total of 120,000 in two different accounts. the first account earns 5% while the second account ears 6% if the total interest earned after one year is 6700 what principal was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #354593 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Investment I 5.00% per annum ---x \n" ); document.write( "Investment II 6.00% per annum ---y \n" ); document.write( " \n" ); document.write( "x + y= 120000 ------------------------1 \n" ); document.write( "5.00% x + 6.00% y= = $6,700.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "5 x + 6 y= = $670,000.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -5 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-5 x -5 y= = -600000.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "0 x 1 y= = $70,000.00 \n" ); document.write( " \n" ); document.write( "divide by 1 \n" ); document.write( " \n" ); document.write( "y = $70,000.00 investment at 6.00% \n" ); document.write( "Balance $50,000.00 investment at 5.00% \n" ); document.write( "CHECK \n" ); document.write( "$50,000.00 --------- 5.00% ------- $2,500.00 \n" ); document.write( "$70,000.00 ------- 6.00% ------- $4,200.00 \n" ); document.write( "Total -------------- $6,700.00 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |