document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=542460>Question 542460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The endpoints of the diameter of a circle are (-3, 2) and (5, -6). Find the center and radius of the circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354583 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The center of the circle will be the midpoint of the line segment representing the diameter<BR>\n" );
document.write( "Given the two endpoints (-3,2) and (5,-6) the midpoint has coordinates <BR>\n" );
document.write( "x = (-3+5)/2 = 1<BR>\n" );
document.write( "y = (2-6)/2 = -2<BR>\n" );
document.write( "The radius is the distance between the center and one of the endpoints:<BR>\n" );
document.write( "r = sqrt((1 - -3)^2 + (-2 - 2)^2) = sqrt(16 + 16) = sqrt(32) = 4*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282%29 ALIGN=MIDDLE  ALT=\"sqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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