document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=542413>Question 542413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> y^2+y=(x+2)^2+y^2+3\r<BR>\n" );
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document.write( "can you help me with the vertices?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354557 by </B><A HREF=/tutors/aboutme.mpl?userid=jpg7n16><B>jpg7n16(66)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jpg7n16><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354557\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok, this problem is easier than it looks because you get to reduce the craziness out of it. If:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y%5E2%2By=%28x%2B2%29%5E2%2By%5E2%2B3 ALIGN=MIDDLE  ALT=\"y%5E2%2By=%28x%2B2%29%5E2%2By%5E2%2B3\"   DISABLED_style= \"max-width:90%; height:auto;\" > subtract y^2 from each side.<BR>\n" );
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document.write( "What that means is that you take a normal x^2 parabola, push it 2 to the left and up 3.<BR>\n" );
document.write( "And parabolas only have 1 vertex. This one will be at the min, when the (x+2)^2 piece is 0. That's at x=-2. So vertex at (-2,3) </SPAN>\n" );
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