document.write( "Question 542374: Phil has 50 nickels and dimes worth $4.15. How many dimes does he have? \n" ); document.write( "
Algebra.Com's Answer #354536 by neatmath(302)\"\" \"About 
You can put this solution on YOUR website!

Our two variables are:
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\n" ); document.write( "\n" ); document.write( "n number of nickels
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\n" ); document.write( "\n" ); document.write( "d number of dimes
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\n" ); document.write( "\n" ); document.write( "Our two equations are now:
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\n" ); document.write( "\n" ); document.write( "\"n%2Bd=50\"
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\n" ); document.write( "\n" ); document.write( "\".05%2An%2B.10%2Ad=4.15\"
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\n" ); document.write( "\n" ); document.write( "We can then solve this system of two equations by elimination or substitution.
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\n" ); document.write( "\n" ); document.write( "I will try substitution. I will solve for n in the first equation:
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\n" ); document.write( "\n" ); document.write( "\"n=50-d\"
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\n" ); document.write( "\n" ); document.write( "Then I will multiply the second equation by 100 to make it easier to deal with:
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\n" ); document.write( "\n" ); document.write( "\"5n%2B10d=415\"
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\n" ); document.write( "\n" ); document.write( "Then I will substitute 50-d in for n in our new equation:
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\n" ); document.write( "\n" ); document.write( "\"5%2A%2850-d%29%2B10d=415\"
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\n" ); document.write( "\n" ); document.write( "\"250-5d%2B10d=415\"
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\n" ); document.write( "\n" ); document.write( "\"250%2B5d=415\"
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\n" ); document.write( "\n" ); document.write( "\"5d=165\"
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\n" ); document.write( "\n" ); document.write( "\"d=33\"
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\n" ); document.write( "\n" ); document.write( "Thus we now know that we have 33 dimes! (which is the answer)
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\n" ); document.write( "\n" ); document.write( "And of course, we also know that we have 17 nickels.
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\n" ); document.write( "\n" ); document.write( "You can easily double check this by using our original second equation.
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\n" ); document.write( "\n" ); document.write( "I hope this helps!
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