document.write( "Question 542271: Two rectangles are similar. One is 5 cm by 12 cm. The longer side of the second rectangle is 8 cm greater than twice it's shorter side. Find it's length and width \n" ); document.write( "

Algebra.Com's Answer #354511 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Two rectangles are similar. One is 5 cm by 12 cm.
\n" ); document.write( " The longer side of the second rectangle is 8 cm greater than twice it's shorter side.
\n" ); document.write( "Find it's length and width.
\n" ); document.write( ":
\n" ); document.write( "Since the rectangles are similar, the relationships between the length and width are the same, so we can write it
\n" ); document.write( ":
\n" ); document.write( "let x = the shorter side
\n" ); document.write( " $\"%28%282x%2B8%29%29%2Fx\"$ = $\"12%2F5\"$
\n" ); document.write( "Cross multiply
\n" ); document.write( "5(2x+8) = 12x
\n" ); document.write( "10x + 40 = 12x
\n" ); document.write( "40 = 12x - 10x
\n" ); document.write( "40 = 2x
\n" ); document.write( "x = 40/2
\n" ); document.write( "x = 20 cm is the shorter side
\n" ); document.write( "then
\n" ); document.write( "2(20)+8 = 48 cm is the length
\n" ); document.write( ":
\n" ); document.write( "The 2nd rectangle: 48 by 20 \n" ); document.write( "

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