document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=542235>Question 542235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the next step in the problem  6 1/3 - 2 2/5 ?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354501 by </B><A HREF=/tutors/aboutme.mpl?userid=friesr><B>friesr(113)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=friesr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you need to get a common denominator. I also like to make them top heavy fractions and reduce them later.<BR>\n" );
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document.write( "6 1/3 = 19/3 and 2 2/5 = 12/5<BR>\n" );
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document.write( "if we multiply 19/3 by 5/5 we get 95/15<BR>\n" );
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document.write( "if we multiply 12/5 by 3/3 we get 36/15<BR>\n" );
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document.write( "95/15 - 36/15 = 59/15<BR>\n" );
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document.write( "Reduced down we get 3 14/15\r<BR>\n" );
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