document.write( "Question 542123: I need help finding the answer of a/2 - a/12 = -5a/4 \n" ); document.write( "
Algebra.Com's Answer #354430 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"a%2F2-a%2F12=-5a%2F4\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"12%28a%2Fcross%282%29-a%2Fcross%2812%29%29=12%28-5a%2Fcross%284%29%29\" Multiply both sides by the LCD \"12\" to clear any fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"6a-1a=-15a\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"5a=-15a\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"5a%2B15a=0\" Add \"15a\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"20a=0\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"a=%280%29%2F%2820%29\" Divide both sides by \"20\" to isolate \"a\".\r
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\n" ); document.write( "\n" ); document.write( "\"a=0\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"a=0\" \r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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