document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=541804>Question 541804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help solve this: find the length of the hypotenuse of a right triangle whose sides are x,(x+1), and (x+3)cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354304 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the formula for the length of a right triangle is a^2 + b^2 = c^2<BR>\n" );
document.write( "a and b are legs of the triangle.<BR>\n" );
document.write( "c is the hypotenuse of the triangle.<BR>\n" );
document.write( "you are given:<BR>\n" );
document.write( "a = x<BR>\n" );
document.write( "b = x+1<BR>\n" );
document.write( "c = x+3<BR>\n" );
document.write( "you need to solve for x.<BR>\n" );
document.write( "the attached file shows the progression.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2011/dec051.jpg\" alt = \"$$$$$\" /><BR>\n" );
document.write( "number 1 shows the formula used.<BR>\n" );
document.write( "number 2 simplifies the equation by multiplying the factors shown.<BR>\n" );
document.write( "number 3 simplifies further by combining like terms.<BR>\n" );
document.write( "number 4 moves everything from the right hand side of the eqution to the left hand side of the equation.<BR>\n" );
document.write( "number 5 combines like terms.<BR>\n" );
document.write( "number 6 places 8 to the right hand side of the equation to prepare for solving by completing the squares method.<BR>\n" );
document.write( "number 7 reformats the equation into completing the square form.<BR>\n" );
document.write( "number 8 combines like terms.<BR>\n" );
document.write( "number 9 takes the square root of both sides of the equation.<BR>\n" );
document.write( "number 10 shows you the results of the operation.<BR>\n" );
document.write( "i tested the results by subsituting for x in the original equation and it checks out so i'm reasonably sure this is the right answer.<BR>\n" );
document.write( "you may want to simplify square root of 12 by showing it as 2 times the square root of 3 (see number 11 in the attached file).<BR>\n" );
document.write( "instructions for completing the square method can be found at this website.<BR>\n" );
document.write( "<a  rel=nofollow HREF= \"http://webgraphing.com/quadraticequation_completingthesquare.jsp\" target = \"_blank\">http://webgraphing.com/quadraticequation_completingthesquare.jsp</a><BR>\n" );
document.write( "you select solving by completing the squares method and enter the equation of x^2 - 4x - 8 = 0 into the box provide and click on solve it and your answer plus step by step instructions shows up.<BR>\n" );
document.write( "if you would rather read how to do it, then go to the following link.<BR>\n" );
document.write( "<a  rel=nofollow HREF= \"http://www.purplemath.com/modules/solvquad3.htm\" target = \"_blank\">http://www.purplemath.com/modules/solvquad3.htm</a> for instructions.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );