document.write( "Question 541703: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 60 mph and train B is traveling at 80 mph. Train A passes the station at 1:15 PM. if train B passes at 1:30 PM what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #354255 by mananth(16946)\"\" \"About 
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the distance traveled by both is same when one catches up with the other.
\n" ); document.write( "Let them meet at distance x
\n" ); document.write( "Train A speed= 60 mph , starts at 01:15 pm
\n" ); document.write( "Train B speed= 80 mph starts at 01:30 pm
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\n" ); document.write( "Time difference between the starting of the two= 0.25 hours
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\n" ); document.write( "Time taken by Train A = X / 60
\n" ); document.write( "Time taken by Train B = X / 80
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\n" ); document.write( "X / 60 - X / 80 = 0.25
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\n" ); document.write( "LCD - 240
\n" ); document.write( "Multiply equation by 240
\n" ); document.write( "240 / 60 x- 240 / 80 x= 0.25 * 240
\n" ); document.write( "4 x - 3 x = 60
\n" ); document.write( "1 x = 60
\n" ); document.write( "/ 1
\n" ); document.write( "x= 60 miles
\n" ); document.write( "Train A speed= 60 mph
\n" ); document.write( "Distance = 60 miles
\n" ); document.write( "Time taken = 60 / 60
\n" ); document.write( "Time taken = 1 hour
\n" ); document.write( "They will be together at 02:15 pm \r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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