document.write( "Question 541690: Three student representatives, a president, a secretary, and a treasurer, are to be chosen from a group of five students: Andrew, Brenda, Chad, Dorothy, and Eric. In how many different ways can the representatives be chosen if the president must be a woman and the secretary and treasurer must be men?\r
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document.write( "My answer is 6, but it's not correct. The correct answer is 12. I don't know why \"12\". \n" );
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Algebra.Com's Answer #354252 by neatmath(302)![]() ![]() You can put this solution on YOUR website! This is one of those counting method problems, using the multiplication principle. \n" ); document.write( "In this case, we have very specific rules for selecting the representatives. \n" ); document.write( "There are 3 positions, how many ways can we \"choose\" each position? \n" ); document.write( "In the first slot, we can only place a woman, so we have 2 choices. \n" ); document.write( "In the second slot, we can only place a man so we have 3 choices. \n" ); document.write( "In the third slot, we can only place a man (who wasn't already chosen), so we have ONLY 2 choices. \n" ); document.write( "This because we assume one person can't be both the secretary and the treasurer at the same time. \n" ); document.write( "Then we just need to multiply the number of choices! \n" ); document.write( "In this case we have \n" ); document.write( " \n" ); document.write( "which equals \n" ); document.write( "I hope this helps! \n" ); document.write( " |