document.write( "Question 541540: If the police have 9 suspects, how many different ways can they select 5 for a lineup?\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #354203 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! Assuming the order does not matter, you want the number of combinations of 9 things taken 5 at a time. \n" ); document.write( ". \n" ); document.write( "The combinations may be denoted as: C(9,5), 9C5 and in several other ways. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The 5! terms cancel \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The above change is because 4*2 cancels the 8 in the numerator and 6/3 = 2 \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |