document.write( "Question 541499: Rowan invested a certain amount of money at 5% per year and an amount thrice as large at 8% per year. The total annual income from the two investment was 17,400 Php. Find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #354195 by Earlsdon(6294)\"\" \"About 
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Let x = the number of Php invested at 5% per annum and 3x = the amount invested at 8% per annum. The sum of the earnings on these two amounts is given as 17,400 Php. (I don't know what these are but we can still work the problem).
\n" ); document.write( "First we write down the expressions for the earnings on each amount. Change the percentages to their decimal equivalents: 5% = 0.05 and 8% = 0.08, then...
\n" ); document.write( "0.05x+0.08(3x) = 17,400 Simplify and solve for x.
\n" ); document.write( "0.05x+0.24x = 17,400 Combine the x's.
\n" ); document.write( "0.29x = 17,400 Divide both sides by 0.29
\n" ); document.write( "x = 60,000 Php and 3x = 180,000 Php.
\n" ); document.write( "60,000 Php was invested at 5% per annum and 180,000 Php was invested at 8% per annum.
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