document.write( "Question 53066: In one year, Cholena Youngblood earned the same amount of interest from an investment at 8%annual interest as an investment at 12% percent annual interest.She had invested $1500 more at 8%.How much money did she invest at 12%. \n" ); document.write( "
Algebra.Com's Answer #35419 by ankor@dixie-net.com(22740)\"\" \"About 
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In one year, Cholena Youngblood earned the same amount of interest from an investment at 8% annual interest as an investment at 12% percent annual interest. She had invested $1500 more at 8%.How much money did she invest at 12%.
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\n" ); document.write( "Let x = amt invested 12%
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\n" ); document.write( "Then [x+1500] = amt invested at 8%
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\n" ); document.write( " The problems states:
\n" ); document.write( "8% int = 12% int
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\n" ); document.write( ".12* x = .08*(x + 1500)
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\n" ); document.write( ".12x = .08x + 120
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\n" ); document.write( ".12x - .08x = 120
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\n" ); document.write( ".04x = 120
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\n" ); document.write( " x = 120/.04
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\n" ); document.write( " x = $3000 invested at 12%
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\n" ); document.write( "amt invested at 8%: 3000 + 1500 = $4500
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\n" ); document.write( "Check: .12(3000) = .08(4500) \r
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