document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=541358>Question 541358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6^(3x-1)=7^(x+1)<BR>\n" );
document.write( "I have tried logging both sides and then moving the exponents in front I think I'm supposed to distribute, but I can't quite remember how.<BR>\n" );
document.write( "so this is where I am at:<BR>\n" );
document.write( "3x-1 log 6 = x+1 log 7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354187 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354187\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-1 log 6 = x+1 log 7<BR>\n" );
document.write( "Find the log of 6 and the log of 7, and you have<BR>\n" );
document.write( ".778(3x-1) = .845(x+1)<BR>\n" );
document.write( "2.334x - .778 = .845x + .845<BR>\n" );
document.write( "2.334x - .845x = .845 + .778<BR>\n" );
document.write( "let you do the math here<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check your solution in the original equation<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );