document.write( "Question 541311: I have to make a graph of this parabola:\r
\n" ); document.write( "\n" ); document.write( "F(x) = x^2 -2x -15\r
\n" ); document.write( "\n" ); document.write( "I need the details of how each of the principals points are calculated.\r
\n" ); document.write( "\n" ); document.write( "Thank you.
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Algebra.Com's Answer #354177 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The easiest point are the intercepts
\n" ); document.write( "x-intercept: (x,0)
\n" ); document.write( "y-intercept: (0,y)
\n" ); document.write( "To find x-intercept(s) ( may be 1 or 2 or none ),
\n" ); document.write( "set \"+f%28x%29+=+0+\" ( f(x) is the same as y )
\n" ); document.write( "\"+f%28x%29+=+x%5E2+-+2x+-+15+\"
\n" ); document.write( "\"+0+=+x%5E2+-+2x+-+15+\"
\n" ); document.write( "\"+x%5E2+-+2x++=+15+\"
\n" ); document.write( "Complete the square by dividing the coefficient
\n" ); document.write( "of the x term by 2, square it, and add it to both sides
\n" ); document.write( "\"+x%5E2+-+2x+%2B+%28-2%2F2%29%5E2+=+15+%2B+%28-2%2F2%29%5E2+\"
\n" ); document.write( "\"+x%5E2+-+2x+%2B+1+=+15+%2B+1+\"
\n" ); document.write( "\"+%28x+-+1%29%5E2+=+4%5E2+\"
\n" ); document.write( "take the square root of both sides
\n" ); document.write( "\"+x+-+1+=+4+\"
\n" ); document.write( "\"+x+=+5+\"
\n" ); document.write( "And, taking the negative root of \"+4%5E2+\"
\n" ); document.write( "\"+x+-+1+=+-4+\"
\n" ); document.write( "\"+x+=+-3+\"
\n" ); document.write( "So, the x-intercepts ( also called roots ) are at
\n" ); document.write( "(5,0) and (-3,0)
\n" ); document.write( "---------------
\n" ); document.write( "To find the y-intercept ( only 1 ), set \"+x=0+\"
\n" ); document.write( "\"+f%28x%29+=+x%5E2+-+2x+-+15+\"
\n" ); document.write( "\"+y+=+0%5E2+-+2%2A0+-+15+\"
\n" ); document.write( "\"+y+=+-15+\"
\n" ); document.write( "y-intercept = (0, -15)
\n" ); document.write( "--------------------
\n" ); document.write( "Now you have 3 important points, also since the
\n" ); document.write( "coefficient of the \"x%5E2\" term is positive, the
\n" ); document.write( "parabola has a minimum, not a maximum.
\n" ); document.write( "The minimum is always exactly between the
\n" ); document.write( "x-intercepts, or at ( (5 - 3)/2, y ) = ( 1, y), and to find y,
\n" ); document.write( "\"+y+=+1%5E2+-+2%2A1+-+15+\"
\n" ); document.write( "\"+y+=+1+-+2+-+15+\"
\n" ); document.write( "\"+y+=+-16+\"
\n" ); document.write( "So, the vertex which is a minimum is at (1, -16)
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