document.write( "Question 541311: I have to make a graph of this parabola:\r
\n" );
document.write( "\n" );
document.write( "F(x) = x^2 -2x -15\r
\n" );
document.write( "\n" );
document.write( "I need the details of how each of the principals points are calculated.\r
\n" );
document.write( "\n" );
document.write( "Thank you. \n" );
document.write( "
Algebra.Com's Answer #354177 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! The easiest point are the intercepts \n" ); document.write( "x-intercept: (x,0) \n" ); document.write( "y-intercept: (0,y) \n" ); document.write( "To find x-intercept(s) ( may be 1 or 2 or none ), \n" ); document.write( "set \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Complete the square by dividing the coefficient \n" ); document.write( "of the x term by 2, square it, and add it to both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "take the square root of both sides \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "And, taking the negative root of \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, the x-intercepts ( also called roots ) are at \n" ); document.write( "(5,0) and (-3,0) \n" ); document.write( "--------------- \n" ); document.write( "To find the y-intercept ( only 1 ), set \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "y-intercept = (0, -15) \n" ); document.write( "-------------------- \n" ); document.write( "Now you have 3 important points, also since the \n" ); document.write( "coefficient of the \n" ); document.write( "parabola has a minimum, not a maximum. \n" ); document.write( "The minimum is always exactly between the \n" ); document.write( "x-intercepts, or at ( (5 - 3)/2, y ) = ( 1, y), and to find y, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So, the vertex which is a minimum is at (1, -16) \n" ); document.write( " |