document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=541315>Question 541315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the inverse of (4-x)/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354147 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354147\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = (4-x)/3\r<BR>\n" );
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document.write( "x = (4-y)/3\r<BR>\n" );
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document.write( "3x = 4-y\r<BR>\n" );
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document.write( "3x - 4 = -y\r<BR>\n" );
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document.write( "-3x + 4 = y\r<BR>\n" );
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document.write( "y = -3x + 4\r<BR>\n" );
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document.write( "So the inverse is -3x + 4\r<BR>\n" );
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document.write( "Jim </SPAN>\n" );
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