document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=541131>Question 541131</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor:\r<BR>\n" );
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document.write( "a) x^2-y^2+3x+y+2<BR>\n" );
document.write( "b) 2x^2-3y^2-5xy+x+11y-6<BR>\n" );
document.write( "c) x^2(y-z)+y^2(z-x)+z^2(x-y)\r<BR>\n" );
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document.write( "I could only begin c) with expanding out the whole expression to:\r<BR>\n" );
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document.write( "x^2(y) - x^2(z) + y^2(z) - xy^2 - yz^2\r<BR>\n" );
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document.write( "I could not even attempt a) or b) and as mentioned above, I began c) with the expansion shown above. \r<BR>\n" );
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document.write( "Any assistance on these three problems would be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #354106 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=354106\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) x^2-y^2+3x+y+2\r<BR>\n" );
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document.write( "Rewrite the equation<BR>\n" );
document.write( "x^2+3x-y^2+y +2\r<BR>\n" );
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document.write( "complete the squares by splitting 2<BR>\n" );
document.write( "9/4 -1/4 = 8/4 =2\r<BR>\n" );
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document.write( "(x^2+3x+9/4) -(y^2-y +1/4)\r<BR>\n" );
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document.write( "(x+3/2)^2- (y-1/2)^2\r<BR>\n" );
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document.write( "Difference of two squares\r<BR>\n" );
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document.write( "(x+3/2+y-1/2)(x+3/2-y+1/2)\r<BR>\n" );
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document.write( "(x+y+1)(x-y+2)<BR>\n" );
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document.write( "b. It is a diophantine equation. to solve it there is a procedure. please look on net\r<BR>\n" );
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document.write( "c) x^2(y-z)+y^2(z-x)+z^2(x-y)\r<BR>\n" );
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document.write( "Using the direct formula for cyclic expressions<BR>\n" );
document.write( "=-(x-y)(y-z)(z-x)\r<BR>\n" );
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document.write( "- </SPAN>\n" );
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