document.write( "Question 541136: how many gallons of 20% alcohol soultion and 50% alcohol soultion must be mixed together to get 9 gallons of 30% alcohol solution?
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Algebra.Com's Answer #354069 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Alcohol I 20 ---------------- x gallons
\n" ); document.write( "Alcohol II 50 ------ 9 - x gallons
\n" ); document.write( "Mixture 30.00% ---------------- 9
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\n" ); document.write( "20x+50( 9-x)=30*9
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\n" ); document.write( "20x+450 -50x= 270
\n" ); document.write( "20x-50x =270-450
\n" ); document.write( "-30x=-180
\n" ); document.write( "/-30
\n" ); document.write( "x = 6 gallons 20.00% Alcohol I
\n" ); document.write( " 3 gallons 50.00% Alcohol II
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\n" ); document.write( "m.ananth@hotmail.ca
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