document.write( "Question 541106: A car drove from one city to another and returned by different route. The outward journey was 48 km and the return journey was 8 km shorter. The speed of the car on the return journey increased by 4 km/h. The return journey took one hour less time. Find the speed of the car on the outward journey. \n" ); document.write( "
Algebra.Com's Answer #354058 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A car drove from one city to another and returned by different route.
\n" ); document.write( " The outward journey was 48 km and the return journey was 8 km shorter.
\n" ); document.write( " The speed of the car on the return journey increased by 4 km/h.
\n" ); document.write( " The return journey took one hour less time.
\n" ); document.write( " Find the speed of the car on the outward journey.
\n" ); document.write( ":
\n" ); document.write( "let t = time of the outward journey (48 km)
\n" ); document.write( "then
\n" ); document.write( "(t-1) = time of the return journey (40km)
\n" ); document.write( ":
\n" ); document.write( "Write speed equation, speed = dist/time
\n" ); document.write( ":
\n" ); document.write( "return speed - outbound speed = 4 km/hr
\n" ); document.write( "\"40%2F%28%28t-1%29%29\" - \"48%2Ft\" = 4 km
\n" ); document.write( ":
\n" ); document.write( "multiply by t(t-1), results:
\n" ); document.write( "40t - 48(t-1) = 4t(t-1)
\n" ); document.write( "40t - 48t + 48 = 4t^2 - 4t
\n" ); document.write( "-8t + 48 = 4t^2 - 4t
\n" ); document.write( "0 = 4t^2 - 4t + 8t - 48
\n" ); document.write( ":
\n" ); document.write( "A quadratic equation
\n" ); document.write( "4t^2 + 4t - 48 = 0
\n" ); document.write( ":
\n" ); document.write( "Simplify, divide by 4
\n" ); document.write( "t^2 + t - 12 = 0
\n" ); document.write( ":
\n" ); document.write( "factors to:
\n" ); document.write( "(t+4)(t-3) = 0
\n" ); document.write( ":
\n" ); document.write( "The positive solution
\n" ); document.write( "t = 3 hrs travel time of the outbound journey
\n" ); document.write( "Find the speed
\n" ); document.write( "\"48%2F3\" = 16 km/hr speed on the outbound journey
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this solution by finding the speed on the return journey
\n" ); document.write( "\"40%2F2\" = 20 km/hr, a 4 km/hr difference
\n" ); document.write( "
\n" ); document.write( "
\n" );