document.write( "Question 540987: A credit card number has 5 digits (between 1 to 9). The first two digits
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document.write( "are 12 in that order, the third digit is bigger than 6, and the fourth digit
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document.write( "is 3 times the 5th digit. How many different credit card combinations are
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document.write( "possible? \n" );
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Algebra.Com's Answer #354027 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Since the first two digits are 12 in that order, there is only 1 way\r\n" ); document.write( "to choose the first two digits. That's 1 way to choose the first\r\n" ); document.write( "two digits.\r\n" ); document.write( "\r\n" ); document.write( "Since the third digit is bigger than 6, it can only be 7,8, or 9.\r\n" ); document.write( "\r\n" ); document.write( "So that's 1×3 choices for the the first three digits.\r\n" ); document.write( "\r\n" ); document.write( "Since the 4th digit is 3 times the 5th digit, the number can only end in \r\n" ); document.write( "31, 62, or 93\r\n" ); document.write( "\r\n" ); document.write( "So for each of the 1×3 way to choose the first 3 digits, there are 3\r\n" ); document.write( "ways to choose the last two digits.\r\n" ); document.write( "\r\n" ); document.write( "That's a total of 1×3×3 = 9 possible numbers. Here are all 9:\r\n" ); document.write( "\r\n" ); document.write( "1. 12731\r\n" ); document.write( "2. 12762\r\n" ); document.write( "3. 12793\r\n" ); document.write( "4. 12831\r\n" ); document.write( "5. 12862\r\n" ); document.write( "6. 12893\r\n" ); document.write( "7. 12931\r\n" ); document.write( "8. 12962\r\n" ); document.write( "9. 12993\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |