document.write( "Question 540986:
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document.write( "Given a normal distribution of values for which the mean is 140 and the
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document.write( "standard deviation is 33, nd the 90th percentile for this distribution.
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document.write( "Round your answers to 3 decimal places. \n" );
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Algebra.Com's Answer #354020 by stanbon(75887) ![]() You can put this solution on YOUR website! Given a normal distribution of values for which the mean is 140 and the \n" ); document.write( "standard deviation is 33, find the 90th percentile for this distribution. \n" ); document.write( "Round your answers to 3 decimal places. \n" ); document.write( "----- \n" ); document.write( "Find the z-value with a left tail of 90% \n" ); document.write( "invNorm(0.90) = 1.2816 \n" ); document.write( "--- \n" ); document.write( "90th %ile score = z*s + u = 1.2816*33 + 140 = 182.291 \n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |