document.write( "Question 53097: Find two consecutive integers such that the sum of 8 times the first integer and 6 times the second integer is 48.No book. Thanks so much! \n" ); document.write( "

Algebra.Com's Answer #35401 by funmath(2933) $\"\"$ $\"About$

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Let the 1st integer=x
\n" ); document.write( "The the 2nd integer=x+1
\n" ); document.write( "Therefore your problem to solve is:
\n" ); document.write( "8x+6(x+1)=48
\n" ); document.write( "8x+6x+6=48
\n" ); document.write( "14x+6=48
\n" ); document.write( "14x+6-6=48-6
\n" ); document.write( "14x=42
\n" ); document.write( "14x/14=42/14
\n" ); document.write( "x=3
\n" ); document.write( "The 1st integer=x=3
\n" ); document.write( "The sencond integer=x+1=3+1=4 \n" ); document.write( "

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