document.write( "Question 539802: Hi I am trying to figure out how to find the equation of a circle if the center is (4,4) and it passes through (-5,0)\r
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document.write( "I know there is an equation that goes with this where you subtract and ^2 power 4-(-5)^2 and (0-4)^2, but that is about all I have figured out & am not sure if it is correct. Thank you for your help.\r
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document.write( "LB \n" );
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Algebra.Com's Answer #353953 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Hi I am trying to figure out how to find the equation of a circle if the center is (4,4) and it passes through (-5,0) \n" ); document.write( "** \n" ); document.write( "Standard form of equation of circle: (x-h)^2+(y-k)^2=r^2, (h,k)=(x,y) coordinates of center, r=radius \n" ); document.write( ".. \n" ); document.write( "Using given coordinates of center (4,4) and point (-5,0) \n" ); document.write( "(-5-4)^2+(0-4)^2=r^2 \n" ); document.write( "(-9)^2+(-4)^2=r^2 \n" ); document.write( "81+16=r^2 \n" ); document.write( "97=r^2 \n" ); document.write( "r=√97 \n" ); document.write( "equation of circle: (x-4)^2+(y-4)^2=97 \n" ); document.write( " |