document.write( "Question 539867: The length of the latus rectum for the ellipse (x^2/64) + (y^2/16) = 1 is equal to:
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document.write( "a)2
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document.write( "b)3
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document.write( "c)4
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document.write( "d)5 \n" );
document.write( "
Algebra.Com's Answer #353950 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The length of the latus rectum for the ellipse (x^2/64) + (y^2/16) = 1 is equal to: \n" ); document.write( "a)2 \n" ); document.write( "b)3 \n" ); document.write( "c)4 \n" ); document.write( "d)5 \n" ); document.write( "** \n" ); document.write( "Standard form of equation for ellipse with horizontal major axis: \n" ); document.write( "(x-h)^2/a^2+(y-k)^2/b^2=1,a>b, (h,k)=(x,y) coordinates of center \n" ); document.write( "From given equation, b^2=16 \n" ); document.write( "a^2=64 \n" ); document.write( "a=8 \n" ); document.write( "Formula for length of the latus rectum for the ellipse: 2b^2/a \n" ); document.write( "2b^2/2a=2*16/8=4 \n" ); document.write( "ans: c)4 \n" ); document.write( " |