document.write( "Question 540958: Solve using the elimination method. I'm messing up somewhere with this, I'm just not sure where, please help.\r
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Algebra.Com's Answer #353945 by AnlytcPhil(1810)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "-2x - 8y = 22\r\n" );
document.write( "-6x -  y = 20\r\n" );
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document.write( "To eliminate y multiply the second equation through by -8\r\n" );
document.write( "to make the term -y into +8y so it will cancel with the\r\n" );
document.write( "-8y term in the first:\r\n" );
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document.write( "-2x - 8y =  22\r\n" );
document.write( "48x + 8y = -80\r\n" );
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document.write( "Now we add term by term:\r\n" );
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document.write( "-2x - 8y =   22\r\n" );
document.write( "48x + 8y = -160\r\n" );
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document.write( "46x      = -138\r\n" );
document.write( "       x = \"%28-138%29%2F46\"\r\n" );
document.write( "       x = -3\r\n" );
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document.write( "Now you can either switch over to substitution or else\r\n" );
document.write( "start over and eliminate x.  \r\n" );
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document.write( "I will start over and eliminate x\r\n" );
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document.write( "-2x - 8y = 22\r\n" );
document.write( "-6x -  y = 20\r\n" );
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document.write( "To eliminate x multiply the first equation through by -3\r\n" );
document.write( "to make the term -2x into +6x so it will cancel with the\r\n" );
document.write( "-6x term in the second:\r\n" );
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document.write( " 6x + 24y = -66\r\n" );
document.write( "-6x -   y =  20\r\n" );
document.write( "---------------\r\n" );
document.write( "      23y = -46\r\n" );
document.write( "        y = \"%28-46%29%2F23\"\r\n" );
document.write( "        y = -2\r\n" );
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document.write( "(x,y) = (-3,-2)\r\n" );
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document.write( "Edwin

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