document.write( "Question 540953: Factor completely:\r
\n" ); document.write( "\n" ); document.write( " $\"%28x%2B1%29%5E3+%2A+x+-+2%28x%2B1%29%5E2+%2A+x%5E2+%2B+x%5E3%28x%2B1%29\"$ \r
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Algebra.Com's Answer #353944 by Theo(13342) $\"\"$ $\"About$

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if we replace (x+1) with a, then we get:
\n" ); document.write( " $\"a%5E3%2Ax+-+2a%5E2%2Ax%5E2+%2B+ax%5E3\"$
\n" ); document.write( "we can factor out an x and an a to get:
\n" ); document.write( " $\"ax%28a%5E2+-+2ax+%2B+x%5E2%29\"$
\n" ); document.write( "we can factor $\"a%5E2+-+2ax+%2B+x%5E2\"$ to get:
\n" ); document.write( " $\"ax%28a-x%29%5E2\"$
\n" ); document.write( "we now replace a with (x+1) to get:
\n" ); document.write( " $\"%28x%2B1%29%2Ax%2A%28%28x%2B1%29-x%29%5E2\"$ \r
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