document.write( "Question 540954: Factor Completely:\r
\n" ); document.write( "\n" ); document.write( " $\"y%5E4+%2A%28y%2B2%29%5E3+%2B+y%5E5+%28y%2B2%29%5E4\"$ \n" ); document.write( "

Algebra.Com's Answer #353942 by Theo(13342) $\"\"$ $\"About$

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if we let a = (y+2), then this expression becomes:
\n" ); document.write( " $\"y%5E4%2Aa%5E3+%2B+y%5E5%2Aa%5E4\"$
\n" ); document.write( "we can factor out a y^4 and an a^3 to get:
\n" ); document.write( " $\"y%5E4a%5E3%281%2Bya%29\"$
\n" ); document.write( "we now replace a with (y+2) to get:
\n" ); document.write( " $\"%28y%5E4%28y%2B2%29%5E3%29%281%2By%28y%2B2%29%29%29\"$
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