document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=540940>Question 540940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f(x) and g(x) and (f of g) functions just confuse me.<BR>\n" );
document.write( "Please help me solve this equation: Given the functions f(x)=2x/x-3 and g(x)=x-2 find a formula, in simplest form, for (f o g)(x).  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353927 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353927\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (f o g)(x) = f(g(x))  <P><BR>\n" );
document.write( "It means first find the value of g(x), then plug that as the variable into f(x).<P><BR>\n" );
document.write( "g(x) = x-2<P><BR>\n" );
document.write( "That's the only value given for g(x), in other words there's no x to plug into g(x) to spit out a number.  So substitute x-2 into f(x).  <P><BR>\n" );
document.write( "f(g(x)) = f(x-2) = (2(x-2))/(x-2-3) = (2x-4)/(x-5) <BR>\n" );
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