document.write( "Question 540907: the length of a rectangle is twice its width. If the peremiter of the rectangle is 48ft, find its area \n" ); document.write( "

Algebra.Com's Answer #353925 by Maths68(1474) $\"\"$ $\"About$

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Perimeter of rectangle = P = 48ft
\n" ); document.write( "Length = 2w
\n" ); document.write( "Width = w\r
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\n" ); document.write( "\n" ); document.write( "Perimeter of rectangle = 2(Length+Width)
\n" ); document.write( "48=2(2w+w)
\n" ); document.write( "48=2(3w)
\n" ); document.write( "48=6w
\n" ); document.write( "48/6=6w/6
\n" ); document.write( "8=w
\n" ); document.write( "w=8ft\r
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\n" ); document.write( "\n" ); document.write( "Length = 2w = 2(8)=16ft
\n" ); document.write( "Width = w = 8ft\r
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\n" ); document.write( "\n" ); document.write( "Area of rectangle = Length * Width
\n" ); document.write( "Area of rectangle = 8 * 16
\n" ); document.write( "Area of rectangle = 128 square feet.\r
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