document.write( "Question 540927: i have tried this problem four times and i keep getting the same ordered triple (2,-5,3). But when i substitute the answer in it does not work. \r
\n" ); document.write( "\n" ); document.write( "1) x + 2y + 2z = -2
\n" ); document.write( "2) 2x - y + 3z = -6
\n" ); document.write( "3) x - 3y + 2z = -7\r
\n" ); document.write( "\n" ); document.write( "1) x + 2y + 2z = -2
\n" ); document.write( "2) (2x - y + 3z = -6)2
\n" ); document.write( " 4x - 2y +6z = -12
\n" ); document.write( " x + 2y + 2z = -2
\n" ); document.write( " NEW 1) 5x + 8z = -14\r
\n" ); document.write( "\n" ); document.write( "2) (2x - y + 3z = -6)-3
\n" ); document.write( "3) x - 3y + 2z = -7
\n" ); document.write( " -6x + 3y - 9z =18
\n" ); document.write( " x - 3y + 2z = -7
\n" ); document.write( " NEW 3) -5x - 7z = 11
\n" ); document.write( " NEW 1) 5x + 8z = -14
\n" ); document.write( " z = 3
\n" ); document.write( "NEW 1)5x + 8z = -14
\n" ); document.write( " 5x + 8(3) = -14
\n" ); document.write( " x = 2
\n" ); document.write( "Original 1) x + 2y + 2z = -2
\n" ); document.write( " 2 + 2y + 2(3) = -2
\n" ); document.write( " 2 + 2y + 6 = -2
\n" ); document.write( " y = -5\r
\n" ); document.write( "\n" ); document.write( " \r
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Algebra.Com's Answer #353915 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
mult eqn 1) by -2 and add to eqn 2) ___ -5y - z = -2 (A)\r
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\n" ); document.write( "\n" ); document.write( "mult eqn 1) by -1 and add to eqn 3) ___ -5y = -5 ___ y = 1\r
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\n" ); document.write( "\n" ); document.write( "substituting ___ -5(1) - z = -2 ___ z = -3\r
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\n" ); document.write( "\n" ); document.write( "substituting ___ x + 2(1) + 2(-3) = -2 ___ x = 2
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