document.write( "Question 540927: i have tried this problem four times and i keep getting the same ordered triple (2,-5,3). But when i substitute the answer in it does not work. \r
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document.write( "1) x + 2y + 2z = -2
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document.write( "2) 2x - y + 3z = -6
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document.write( "3) x - 3y + 2z = -7\r
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document.write( "1) x + 2y + 2z = -2
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document.write( "2) (2x - y + 3z = -6)2
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document.write( " 4x - 2y +6z = -12
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document.write( " x + 2y + 2z = -2
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document.write( " NEW 1) 5x + 8z = -14\r
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document.write( "2) (2x - y + 3z = -6)-3
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document.write( "3) x - 3y + 2z = -7
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document.write( " -6x + 3y - 9z =18
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document.write( " x - 3y + 2z = -7
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document.write( " NEW 3) -5x - 7z = 11
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document.write( " NEW 1) 5x + 8z = -14
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document.write( " z = 3
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document.write( "NEW 1)5x + 8z = -14
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document.write( " 5x + 8(3) = -14
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document.write( " x = 2
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document.write( "Original 1) x + 2y + 2z = -2
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document.write( " 2 + 2y + 2(3) = -2
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document.write( " 2 + 2y + 6 = -2
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document.write( " y = -5\r
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document.write( "
Algebra.Com's Answer #353913 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! i have tried this problem four times and i keep getting the same ordered triple (2,-5,3). But when i substitute the answer in it does not work. \n" ); document.write( "1) x + 2y + 2z = -2 \n" ); document.write( "2) 2x - y + 3z = -6 \n" ); document.write( "3) x - 3y + 2z = -7 \n" ); document.write( "========================= \n" ); document.write( "x = 2 \n" ); document.write( "y = 1 \n" ); document.write( "z = -3 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |