document.write( "Question 540840: There are two different ways to put the digits 1,2,3,4, and 5 into the blanks between the parentheses, one digit per blank, so that \r
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Algebra.Com's Answer #353899 by AnlytcPhil(1810)\"\" \"About 
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document.write( "There are three odd number and two even numbers among 1,2,3,4,5.\r\n" );
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document.write( "The only way the left side could be odd would be for all three odds\r\n" );
document.write( "to be on the left side.  Then the two evens would have to be on\r\n" );
document.write( "the right making the right side even.  Since the left side cannot be odd,\r\n" );
document.write( "neither can the right side. So both sides are even.\r\n" );
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document.write( "Since both evens, 2 and 4 cannot be on the right, and the right must be even,\r\n" );
document.write( "then the two numbers on the right are odd.  So we have two evens and one odd\r\n" );
document.write( "on the left and two odds on the right.\r\n" );
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document.write( "So we either have\r\n" );
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document.write( "EVEN×EVEN÷ODD = ODD + ODD  or\r\n" );
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document.write( "EVEN×ODD÷EVEN = ODD + ODD\r\n" );
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document.write( "Neither 3,4, nor 5 will divide evenly into the product of any\r\n" );
document.write( "two of the other numbers, so the divided number on the left is either\r\n" );
document.write( "1 or 2.  So we have either\r\n" );
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document.write( "EVEN×EVEN÷1 = ODD + ODD or\r\n" );
document.write( "EVEN×ODD÷2 = ODD + ODD\r\n" );
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document.write( "The first case can only be\r\n" );
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document.write( "2×4÷1 = 3 + 5  which is a solution\r\n" );
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document.write( "The second case can only be\r\n" );
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document.write( "4×ODD÷2 = ODD + ODD\r\n" );
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document.write( "The added odd numbers on the\r\n" );
document.write( "right are either 1+3, 1+5, or 3+5 or 8. So the right side\r\n" );
document.write( "is either 4,6, or 8\r\n" );
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document.write( "The odd number on the left cannot be 1, since the right side cannot be\r\n" );
document.write( "2.\r\n" );
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document.write( "The odd number on the left cannot be 5, since the right side cannot be\r\n" );
document.write( "10.\r\n" );
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document.write( "So, the odd number on the left can only be 3, making the right side\r\n" );
document.write( "3+5 or 8.\r\n" );
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document.write( "Therefore the two solutions are:\r\n" );
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document.write( "2×4÷1 = 3 + 5  and 3×4÷2 = 1 + 5\r\n" );
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document.write( "Edwin
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