document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=540841>Question 540841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help with this equation:   Solve the linerar system using the substitution method.   x-2y=4<BR>\n" );
document.write( "                      2x-3y=1<BR>\n" );
document.write( "work done:<BR>\n" );
document.write( "         equation 1 x= 2y+4<BR>\n" );
document.write( "         equation 2 2(2y+4)-3y=1<BR>\n" );
document.write( "                      y=-7 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #353891 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=353891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equation 1 x= 2y+4<BR>\n" );
document.write( "equation 2 2(2y+4)-3y=1\r<BR>\n" );
document.write( "\n" );
document.write( "4y+8-3y=1<BR>\n" );
document.write( "y=-7\r<BR>\n" );
document.write( "\n" );
document.write( "plug value of y in equation (1)<BR>\n" );
document.write( "x=2(-7)+4<BR>\n" );
document.write( "x=-14+4<BR>\n" );
document.write( "x=-10<BR>\n" );
document.write( "          </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );