document.write( "Question 540816: An airplane traveled a distance of 400 km at an average speed of x km/h. Write down an expression for the time taken. On the return journey, the speed increased by 40 km/h. Write down an expression for the time for the return journey. If the return journey took 30 minutes less than the outward journey, write down an equation in x and solve it. \n" ); document.write( "
Algebra.Com's Answer #353890 by mananth(16946)\"\" \"About 
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distance = 400
\n" ); document.write( "speed = x\r
\n" ); document.write( "\n" ); document.write( "t=400/x\r
\n" ); document.write( "\n" ); document.write( "speed increased by 40 on return\r
\n" ); document.write( "\n" ); document.write( "t= 400/(x+40)\r
\n" ); document.write( "\n" ); document.write( "400/x-400/(x+40)=1/2\r
\n" ); document.write( "\n" ); document.write( "Lcd = x(x+40)
\n" ); document.write( "multiply the equation by the LCD\r
\n" ); document.write( "\n" ); document.write( "400(x+40)-400x=x(x+40)/2
\n" ); document.write( "400x+16000-400x=(x^2+40x)/2
\n" ); document.write( "16000=(x^2+40x)/2
\n" ); document.write( "multiply equation by 2
\n" ); document.write( "32000 - x^2+40x
\n" ); document.write( "x^2+40x-32000=0\r
\n" ); document.write( "\n" ); document.write( "x^2+200x-160x-32000=0
\n" ); document.write( "x(x+200)-160(x+200)=0
\n" ); document.write( "(x+200)(x-160)=0
\n" ); document.write( "x= -200 OR 160
\n" ); document.write( "neglect negative value
\n" ); document.write( "The speed = 160 km/h\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( "
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