document.write( "Question 540637: Rather confused about what's going on here. My book doesn't offer an explanation on what I should do with this type of set up. \r
\n" ); document.write( "\n" ); document.write( "Write an equation for each ellipse.\r
\n" ); document.write( "\n" ); document.write( "\"foci at (-3,-3), (7,-3); the point (2,-7) on ellipse\"
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Algebra.Com's Answer #353875 by lwsshak3(11628)\"\" \"About 
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Write an equation for each ellipse.
\n" ); document.write( "\"foci at (-3,-3), (7,-3); the point (2,-7) on ellipse
\n" ); document.write( "**
\n" ); document.write( "Given data shows equation is that of an ellipse with horizontal major axis of the standard form
\n" ); document.write( "(x-h)^2/a^2+(y-k)^2/b^2=1, a>b, (h,k) being the (x,y) coordinates of the center. (x-coordinates of foci changes while y-coordinates do not).
\n" ); document.write( "..
\n" ); document.write( "For given equation:
\n" ); document.write( "x-coordinate of center=(7+(-3))/2=4/2=2
\n" ); document.write( "y-coordinate of center=-3
\n" ); document.write( "center:(2,-3)
\n" ); document.write( "c=distance from center to focus on major axis=5
\n" ); document.write( "c^2=25
\n" ); document.write( "..
\n" ); document.write( "solving for a and b in standard form of equation for ellipse:
\n" ); document.write( "Sum of the distance from point (2,-7) on ellipse to each of the two focal points=2a
\n" ); document.write( "Using distance formula:√[(x1-x2)^2+(y1-y^2)^2]+√[(x1-x2)^2+(y1-y^2)^2]=2a
\n" ); document.write( "√[(2+3)^2+(-7+3)^2]+√[(2-7)^2+(-7+3)^2]=2a
\n" ); document.write( "√[(5)^2+(-4)^2]+√[(-5)^2+(-4)^2]=2a
\n" ); document.write( "√[25+16]+√[25+16]=2a
\n" ); document.write( "√[41]+√[41]=2√41=2a
\n" ); document.write( "a=√41
\n" ); document.write( "a^2=41
\n" ); document.write( "..
\n" ); document.write( "c^2=a^2-b^2
\n" ); document.write( "b^2=a^2-c^2=41-25=16
\n" ); document.write( "..
\n" ); document.write( "Equation of given ellipse:
\n" ); document.write( "(x-2)^2/41+(y+3)^2/16=1
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