document.write( "Question 539049: find compound interest on $450 for 2 years at 10% per annum compounded yearly\r
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Algebra.Com's Answer #353874 by jpg7n16(66)\"\" \"About 
You can put this solution on YOUR website!
Use this formula:
\n" ); document.write( "\"p%2A%28%281%2Bi%29%5En%29=x\"
\n" ); document.write( "p=original principal
\n" ); document.write( "i=interest rate per compounding period
\n" ); document.write( "n=number of compounding periods
\n" ); document.write( "x=new amount of money
\n" ); document.write( "So start pulling pieces from the question.
\n" ); document.write( "-What was the original amount you started with? $450 (p)
\n" ); document.write( "-What is the interest rate per compounding period? 10% (i)
\n" ); document.write( "-How many times does it compound? 2 (n)
\n" ); document.write( "-We are looking for X
\n" ); document.write( "So take the original formula
\n" ); document.write( "\"p%2A%28%281%2Bi%29%5En%29=x\"
\n" ); document.write( "substitute in what you know, and solve for X
\n" ); document.write( "\"450%2A%28%281%2B.10%29%5E2%29=x\"
\n" ); document.write( "\"x=450%2A%281.1%5E2%29=450%2A1.21=544.50\"
\n" ); document.write( "So you started with $450 and ended with $544.50. How much does that mean you earned?
\n" ); document.write( "\"544.50-450=94.50\"
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