document.write( "Question 540746: A boy who is 4 feet 6 inches tall casts a shadow that is 6 feet 3 inches long. What is the height of a tree that casts a shadow that is 25 feet long?\r
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document.write( "I know that it is direct variation and that I need to use the equation y=kx. In my instruction, however, there were only example problems in which x was changed. I may be completely off base but I assumed that I could do the equation as followed:\r
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document.write( "y(height of boy)=4.6; x(shadow)=6.25
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document.write( "solve for y=6.25
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document.write( "y(k)=x
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document.write( "k(25)=6.25
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document.write( "k(25)/6.25 = 6.25/6.25
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document.write( "k=4\r
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document.write( "4.6 (4) = x
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document.write( "x=18.4\r
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document.write( "18 is an answer... but that doesn't seem right.\r
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document.write( "And then I realized that something terribly wrong happened. Thank you so much to who ever might decide to help! \n" );
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Algebra.Com's Answer #353863 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! x and y represent an object and its shadow \n" ); document.write( "___ it makes no difference which letter represents which parameter, as long as you are consistent \n" ); document.write( "___ yes, this is a direct variation; bigger objects have bigger shadows\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let x be the object and y the shadow \n" ); document.write( "___ work in consistent units ___ feet, in this case\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6.25 = k * 4.5 ___ k = 6.25 / 4.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25 = k * x ___ 25 / k = x ___ 25 / (6.25 / 4.5) = x ___ 18 = x\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you did find the right answer, but your technique needs work (you were lucky...) \n" ); document.write( " |