document.write( "Question 540745: This is the last one that I am struggling with.\r
\n" ); document.write( "\n" ); document.write( "2r-2/ r^2+3r-28 + 4/r+7 = r/r-4\r
\n" ); document.write( "\n" ); document.write( "This should read 2r-2 over r squared plus 3r minus 28 plus 4 over r+7 equals 1 over r-4.
\n" ); document.write( "

Algebra.Com's Answer #353845 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "I am assuming the last fraction is 1/(r-4) as you said in the text
\n" ); document.write( ":
\n" ); document.write( "\"%28%282r-2%29%29%2F%28%28r%5E2%2B3r-28%29%29\" + \"4%2F%28%28r%2B7%29%29\" = \"1%2F%28%28r-4%29%29\"
\n" ); document.write( "Factor the 1st denominator and this will all make sense
\n" ); document.write( "\"%28%282r-2%29%29%2F%28%28r%2B7%29%28r-4%29%29\" + \"4%2F%28%28r%2B7%29%29\" = \"1%2F%28%28r-4%29%29\"
\n" ); document.write( "Multiply by (r+7)(r-4), cancels the denominators and you have
\n" ); document.write( "2r - 2 + 4(r-4) = r + 7
\n" ); document.write( "2r - 2 + 4r - 16 = r + 7
\n" ); document.write( "6r - 18 = r + 7
\n" ); document.write( "6r - r = 7 + 18
\n" ); document.write( "5r = 25
\n" ); document.write( "r = 25/5
\n" ); document.write( "r = 5
\n" ); document.write( "You can check this solution in the original equation
\n" ); document.write( "
\n" ); document.write( "
\n" );