document.write( "Question 540745: This is the last one that I am struggling with.\r
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document.write( "2r-2/ r^2+3r-28 + 4/r+7 = r/r-4\r
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document.write( "This should read 2r-2 over r squared plus 3r minus 28 plus 4 over r+7 equals 1 over r-4. \n" );
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Algebra.Com's Answer #353845 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I am assuming the last fraction is 1/(r-4) as you said in the text \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "Factor the 1st denominator and this will all make sense \n" ); document.write( " \n" ); document.write( "Multiply by (r+7)(r-4), cancels the denominators and you have \n" ); document.write( "2r - 2 + 4(r-4) = r + 7 \n" ); document.write( "2r - 2 + 4r - 16 = r + 7 \n" ); document.write( "6r - 18 = r + 7 \n" ); document.write( "6r - r = 7 + 18 \n" ); document.write( "5r = 25 \n" ); document.write( "r = 25/5 \n" ); document.write( "r = 5 \n" ); document.write( "You can check this solution in the original equation \n" ); document.write( " \n" ); document.write( " |