document.write( "Question 540712: paddling with a current a canoeist can travel 48 miles in 3 hours. against the current he takes 4 hours to travel the same distance. find the rate of the canoeist in still water and the rate of the current \n" ); document.write( "
Algebra.Com's Answer #353829 by mananth(16946)\"\" \"About 
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Canoe speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current , x-y 4 hours
\n" ); document.write( "with current , x+y 3 hours
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\n" ); document.write( "Distance = same= 48 miles
\n" ); document.write( "t=d/r
\n" ); document.write( "Against current
\n" ); document.write( "48 / ( x - y )= 4.00
\n" ); document.write( "4 ( x - y ) = 48.00
\n" ); document.write( "4 x -4 y = 48 ....................1\r
\n" ); document.write( "\n" ); document.write( "With current
\n" ); document.write( "48 / ( x + y )= 3.00
\n" ); document.write( "3.00 ( x + y ) = 48
\n" ); document.write( "3.00 x + 3.00 y = 48 ...............2
\n" ); document.write( "Multiply (1) by 3.00
\n" ); document.write( "Multiply (2) by 4.00
\n" ); document.write( "we get
\n" ); document.write( "12 x + -12 y = 144
\n" ); document.write( "12 x + 12 y = 192
\n" ); document.write( "24 x = 336
\n" ); document.write( "/ 24
\n" ); document.write( "x = 14 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "4 x -4 y = 48
\n" ); document.write( "56 -4 y = 48
\n" ); document.write( "-4 y = 48 -56
\n" ); document.write( "-4 y = -8
\n" ); document.write( " y = 2 mph
\n" ); document.write( " Canoe 14 mph
\n" ); document.write( " current 2 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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