document.write( "Question 540649: solve by completing the square:\r
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document.write( "x^2-22x-4=0 \n" );
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Algebra.Com's Answer #353811 by mananth(16946)![]() ![]() You can put this solution on YOUR website! x^2-22x-4\r \n" ); document.write( "\n" ); document.write( "x^2-22x+121-4 =121\r \n" ); document.write( "\n" ); document.write( "x^2-22x+121=121+4\r \n" ); document.write( "\n" ); document.write( "(x-11)^2=125\r \n" ); document.write( "\n" ); document.write( "(x-11)^2=25*(5)\r \n" ); document.write( "\n" ); document.write( "Take the square root on both sides\r \n" ); document.write( "\n" ); document.write( "x-11= +/- 5sqrt(5)\r \n" ); document.write( "\n" ); document.write( "x=11+5sqrt(5) \n" ); document.write( "OR \n" ); document.write( "x=11-5sqrt(5) \n" ); document.write( " |