document.write( "Question 540383: solve this system algebraically y=x2-5
\n" ); document.write( " y= x+1
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Algebra.Com's Answer #353747 by ankor@dixie-net.com(22740)\"\" \"About 
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y = x^2 - 5
\n" ); document.write( "y = x + 1
\n" ); document.write( "Since y = y, we can write it
\n" ); document.write( "x^2 - 5 = x + 1
\n" ); document.write( "x^2 - x - 5 - 1 = 0
\n" ); document.write( "x^2 - x - 6 = 0; our old friend, the quadratic equation!
\n" ); document.write( "Factors to
\n" ); document.write( "(x-3)(x+2) = 0
\n" ); document.write( "x = 3
\n" ); document.write( "x = -2
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\n" ); document.write( "Find y when x=3
\n" ); document.write( "y = 3 + 1
\n" ); document.write( "y = 4
\n" ); document.write( "Find y when x=-2
\n" ); document.write( "y = -2 + 1
\n" ); document.write( "y = -1
\n" ); document.write( ":
\n" ); document.write( "You should check both pairs of solutions in the 1st equation
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